The average of four consecutive even is 27.Find value of the largest these number
Let's call the smallest even number "x".
Since the even numbers are consecutive, we can express the four even numbers as x, x+2, x+4, and x+6.
We know that the average of these four numbers is 27, so we can set up an equation:
(x + (x+2) + (x+4) + (x+6))/4 = 27
Simplifying and solving for x:
(4x + 12)/4 = 27
4x + 12 = 108
4x = 96
x = 24
Therefore, the largest even number is x+6, which is 24+6 = 30.
To find the largest of four consecutive even numbers with an average of 27, we can start by determining the smallest number in the sequence.
Since the numbers are consecutive even numbers, we can write them as x, x+2, x+4, and x+6, where x is the smallest number.
The average of these four numbers is given as 27, so we can set up the following equation:
(x + x + 2 + x + 4 + x + 6)/4 = 27
Simplifying this equation gives us:
(4x + 12)/4 = 27
Multiplying both sides by 4:
4x + 12 = 108
Subtracting 12 from both sides:
4x = 96
Dividing both sides by 4:
x = 24
Therefore, the smallest number in the sequence is 24.
To find the largest number, we simply add 6 to the smallest number:
24 + 6 = 30
Hence, the largest of these four consecutive even numbers is 30.