A bag contains 4 white, 3 blue, and 5 red marbles.
Find the probability of choosing a red marble, then a white marble if the marbles are replaced.
A. one-twelfth
B. five over thirty-six
C. five-sixths
D. five-twelfths.
The probability of choosing a red marble on the first draw is 5/12. Since the marbles are replaced, the probability of choosing a white marble on the second draw is also 4/12 or 1/3.
To find the probability of both events happening together (i.e. choosing a red marble and then a white marble), we multiply the probabilities:
5/12 * 1/3 = 5/36
So the answer is B. five over thirty-six.
To find the probability of choosing a red marble, then a white marble if the marbles are replaced, we need to calculate the probability of each event separately and then multiply them together.
First, let's calculate the probability of choosing a red marble:
Total number of marbles = 4 (white) + 3 (blue) + 5 (red) = 12
Probability of choosing a red marble = number of red marbles / total number of marbles = 5 / 12
Next, let's calculate the probability of choosing a white marble:
Total number of marbles (after replacing) = 4 (white) + 3 (blue) + 5 (red) = 12
Probability of choosing a white marble = number of white marbles / total number of marbles = 4 / 12 = 1 / 3
Now, to find the probability of both events happening, we multiply the probabilities:
Probability of choosing a red marble, then a white marble = (5 / 12) * (1 / 3)
Simplifying,
Probability of choosing a red marble, then a white marble = 5 / 36
Therefore, the correct answer is B. five over thirty-six.