A student solved the following equation using the following steps:
2(2x + 2) = 4(x + 4)
4x + 4 = 4x + 4
4 = 4
Infinite solutions
Based on the student's work, the equation was solved .
The equation solved correctly would show that it has solution(s).
Word Bank:
correctlyinfinitethreenonoincorrectlytwo
Blank 1:
Blank 2:
Blank 1: incorrectly
Blank 2: infinite
plz do not get this wrong whai is the CORRECT answer
A student solved the following equation using the following steps:
2(2x + 2) = 4(x + 4)
4x + 4 = 4x + 4
4 = 4
Infinite solutions
Based on the student's work, the equation was solved .
The equation solved correctly would show that it has solution(s).
Word Bank:
correctlyinfinitethreenonoincorrectlytwo
Blank 1:
Blank 2:
Blank 1: correctly
Blank 2: infinite
2(2x + 2) = 4(x + 4)
2(2x + 2) = 4(x + 4)
4x + 4 = 4x + 16
4x - 4x = 16 - 4
0 = 12
There is no solution to this equation because 0 can never equal 12.
The equation 7x - 11 = 6x - x - 11 has the same solution as 5(x + 4) = 7x - 14 ?
True
False
True.
We can simplify the first equation as:
7x - 11 = 6x - x - 11
Simplifying the right-hand side by combining like terms,
7x - 11 = 5x - 11
Subtracting 5x from both sides, we get
2x - 11 = -11
Adding 11 to both sides we get
2x = 0
Dividing by 2 on both sides of the equation, we get
x = 0
Now, we can simplify the second equation as:
5(x + 4) = 7x - 14
Expanding the left-hand side, we get
5x + 20 = 7x - 14
Subtracting 5x from both sides, we get
20 = 2x - 14
Adding 14 to both sides, we get
34 = 2x
x = 17
Therefore, the solutions of both the equations are different and 5(x + 4) = 7x - 14 does not have the same solution as 7x - 11 = 6x - x - 11. The statement is False.
7x - 11 = 6x - x - 11
7x - 11 = 6x - x - 11
Simplifying the right-hand side by combining like terms, we get:
7x - 11 = 5x - 11
Subtracting 5x from both sides, we get:
2x - 11 = -11
Adding 11 to both sides, we get:
2x = 0
Dividing by 2 on both sides of the equation, we get:
x = 0
Therefore, the solution to this equation is x = 0.