Identify the substance oxidized reduced oxidizingagent reducing agent depending on the reaction below 3No2+H2o=2HNO3+No?
The substance that is oxidized in this reaction is NO2, which is converted to HNO3 and NO. The substance that is reduced is H2O, which loses its hydrogen atoms. The oxidizing agent is H2O, which is oxidized. The reducing agent is NO2, which is reduced.
To determine the substance oxidized, reduced, oxidizing agent, and reducing agent in the given reaction:
Reaction: 3NO2 + H2O -> 2HNO3 + NO
1. Identify the oxidation states of each element in the reaction:
- Nitrogen (N) in NO2 has an oxidation state of +4.
- Hydrogen (H) in H2O has an oxidation state of +1.
- Nitrogen (N) in HNO3 has an oxidation state of +5.
- Nitrogen (N) in NO has an oxidation state of +2.
2. Compare the oxidation states before and after the reaction:
- The oxidation state of nitrogen goes from +4 in NO2 to +5 in HNO3. Therefore, nitrogen is oxidized.
- The oxidation state of nitrogen goes from +4 in NO2 to +2 in NO. Therefore, nitrogen is reduced.
- The oxidation state of hydrogen remains the same at +1.
- The oxidation state of oxygen goes from -2 in H2O to -2 in HNO3. Therefore, oxygen is neither oxidized nor reduced.
3. Identify the oxidizing agent and reducing agent:
- The substance that causes the oxidation of another species is the oxidizing agent. In this case, NO2 is the oxidizing agent.
- The substance that causes the reduction of another species is the reducing agent. In this case, H2O is the reducing agent.
To summarize:
- The substance oxidized is NO2.
- The substance reduced is H2O.
- The oxidizing agent is NO2.
- The reducing agent is H2O.