Which of the following is a true statement?
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It is possible for two rectangles to have the same area, but only if they also have the same perimeter.
It is possible for two squares to have the same area without having the same perimeter.
It is possible for two squares to have the same perimeter without having the same area.
It is possible for two rectangles to have the same area without having the same perimeter.
It is possible for two rectangles to have the same area without having the same perimeter.
Each pail of plaster covers 90 square feet of ceiling. What is the least number of pails of plaster you would need to buy to cover the ceiling of a square room with walls 20 feet long?
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5 pails
6 pails
4 pails
3 pails
The area of the ceiling is equal to the area of the square room, which is (20 feet) x (20 feet) = 400 square feet. To find the number of pails needed, divide the area of the ceiling by the area covered by each pail:
400 square feet ÷ 90 square feet/pail ≈ 4.44
Since you can't buy partial pails, you would need to buy at least 5 pails of plaster to cover the ceiling.
Answer: 5 pails
Find the perimeter of the rectangle with length 26 inches and 31 inches?
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228 inches
211 inches
1,649 inches
114 inches
Perimeter of a rectangle is given by the formula:
Perimeter = 2 x (length + width)
In this problem, the length is 31 inches and the width is 26 inches.
So,
Perimeter = 2 x (31 inches + 26 inches)
Perimeter = 2 x 57 inches
Perimeter = 114 inches
Therefore, the perimeter of the rectangle is 114 inches.
Answer: 114 inches
The area of the large rectangle is twice the area of the small rectangle. What is the value of s?
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3
8
96
192
We can set up an equation to solve for s.
Let the length of the small rectangle be l and its width be w. Then, its area is lw.
Let the length of the large rectangle be 2l (since we're told the area is twice that of the small rectangle) and its width be s. Then, its area is 2lw.
So we have:
2lw = 2(l x s)
lw = ls
Divide both sides by l:
w = s
We know that the length of the small rectangle is 3s and the width is s, so:
lw = 3s^2
s^2 = (lw)/3
s^2 = (3s^2)/3
s^2 = s^2
Therefore, we get s^2 = 0, which means s = 0.
This doesn't make sense, so there must be an error in the problem statement or the options provided.
Answer: None of the options provided.