What is the mean absolute deviation of the following dataset: 4.8, 5.9, 6.2, 10.8, 1.2, 6.4? Round the answer to the nearest tenth.(1 point)
To find the mean absolute deviation, we first need to find the mean of the dataset:
Mean = (4.8 + 5.9 + 6.2 + 10.8 + 1.2 + 6.4) / 6 = 5.73
Next, we find the absolute deviation of each number by subtracting the mean from each number and taking the absolute value:
|4.8 - 5.73| = 0.93
|5.9 - 5.73| = 0.17
|6.2 - 5.73| = 0.47
|10.8 - 5.73| = 5.07
|1.2 - 5.73| = 4.53
|6.4 - 5.73| = 0.67
Then, we find the average of the absolute deviations:
(0.93 + 0.17 + 0.47 + 5.07 + 4.53 + 0.67) / 6 = 1.95
Therefore, the mean absolute deviation of the dataset is approximately 1.9 when rounded to the nearest tenth.
Bot
BOT I NEED HELP
HELP
What is the mean absolute deviation of the following dataset: 4.8, 5.9, 6.2, 10.8, 1.2, 6.4? Round the answer to the nearest tenth.(1 point)
The number of words Mr. Ahmad’s students read per minute is 109, 89, 112, 98, 101, 105, 120, 106. What is the mean absolute deviation of the dataset? Round the answer to the nearest tenth.
To find the mean absolute deviation, we first need to find the mean of the dataset:
Mean = (109 + 89 + 112 + 98 + 101 + 105 + 120 + 106) / 8 = 104.5
Next, we find the absolute deviation of each number by subtracting the mean from each number and taking the absolute value:
|109 - 104.5| = 4.5
|89 - 104.5| = 15.5
|112 - 104.5| = 7.5
|98 - 104.5| = 6.5
|101 - 104.5| = 3.5
|105 - 104.5| = 0.5
|120 - 104.5| = 15.5
|106 - 104.5| = 1.5
Then, we find the average of the absolute deviations:
(4.5 + 15.5 + 7.5 + 6.5 + 3.5 + 0.5 + 15.5 + 1.5) / 8 = 6.875
Therefore, the mean absolute deviation of the dataset is approximately 6.9 when rounded to the nearest tenth.
thats wrong
I apologize for the mistake. Here's the correct solution:
To find the mean absolute deviation, we first need to find the mean of the dataset:
Mean = (109 + 89 + 112 + 98 + 101 + 105 + 120 + 106) / 8 = 104.5
Next, we find the absolute deviation of each number by subtracting the mean from each number and taking the absolute value:
|109 - 104.5| = 4.5
|89 - 104.5| = 15.5
|112 - 104.5| = 7.5
|98 - 104.5| = 6.5
|101 - 104.5| = 3.5
|105 - 104.5| = 0.5
|120 - 104.5| = 15.5
|106 - 104.5| = 1.5
Then, we find the average of the absolute deviations:
(4.5 + 15.5 + 7.5 + 6.5 + 3.5 + 0.5 + 15.5 + 1.5) / 8 = 6.875
Therefore, the mean absolute deviation of the dataset is approximately 6.9 when rounded to the nearest tenth.