A spring of force constant at 1500Nm-1is acted upon by a constant force of 75N calculate the potential energy stored in the spring
The potential energy stored in a spring is given by the formula:
PE = (1/2)kx^2
Where k is the spring constant and x is the displacement from the equilibrium position.
In this case, the spring constant is 1500 N/m and the force acting on the spring is 75 N. We can use Hooke's Law to find the displacement:
F = kx
75 N = 1500 N/m * x
x = 0.05 m
Now we can use the formula for potential energy:
PE = (1/2)kx^2
PE = (1/2) * 1500 N/m * (0.05 m)^2
PE = 1.875 J
Therefore, the potential energy stored in the spring is 1.875 J.
To calculate the potential energy stored in a spring, you can use the formula:
Potential Energy (U) = (1/2) * k * x^2
where k is the force constant of the spring, and x is the displacement from the equilibrium position.
In this case, the force constant (k) is given as 1500 N/m, and the constant force acting on the spring is 75 N.
To find the displacement (x), we need to rearrange the formula for force F, which is given by:
F = k * x
Rearranging the formula for x:
x = F / k
Substituting the given values:
x = 75 N / 1500 N/m
x = 0.05 m
Now we can calculate the potential energy (U) using the formula:
U = (1/2) * k * x^2
Substituting the values:
U = (1/2) * 1500 N/m * (0.05 m)^2
U = (1/2) * 1500 N/m * 0.0025 m^2
U = 1.875 J
Therefore, the potential energy stored in the spring is 1.875 Joules.