A researcher tagged 40 giant turtles in 2008. In 2009, she returned and captured 50 turtles, 16 of which were tagged. In 2010, she returned again and captured 30 turtles, 8 of which were tagged.

Use a proportion to estimate the turtle population for 2009.
Use a proportion to estimate the turtle population for 2010..

For 2009:

Let x be the turtle population for 2009.
The proportion can be set up as:

tagged turtles in 2009 / total number of turtles in 2009 = tagged turtles in 2008 / total number of turtles in 2008

Plugging in the known values, we get:

16 / 50 = 40 / x

Cross-multiplying and solving for x, we get:

x = 125

So, the estimated turtle population for 2009 is 125.

For 2010:

Let y be the turtle population for 2010.
The proportion can be set up as:

tagged turtles in 2010 / total number of turtles in 2010 = tagged turtles in 2008 / total number of turtles in 2008

Plugging in the known values, we get:

8 / 30 = 40 / y

Cross-multiplying and solving for y, we get:

y = 150

So, the estimated turtle population for 2010 is 150.

To estimate the turtle population for 2009 using a proportion, we can set up the following proportion:

(Number of tagged turtles in 2009) / (Total number of turtles captured in 2009) = (Number of tagged turtles in 2008) / (Total population of turtles in 2008)

Let's substitute the given values into this proportion:

(16) / (50) = (40) / (x)

To solve for x, we can cross-multiply:

16 * x = 40 * 50
16x = 2000

Divide both sides by 16 to isolate x:

x = 2000 / 16
x = 125

So, we can estimate that the turtle population in 2009 was approximately 125.

Now, let's estimate the turtle population for 2010 using a similar proportion:

(Number of tagged turtles in 2010) / (Total number of turtles captured in 2010) = (Number of tagged turtles in 2008) / (Total population of turtles in 2008)

Substituting the given values:

(8) / (30) = (40) / (x)

Cross-multiplying:

8 * x = 40 * 30
8x = 1200

Dividing by 8:

x = 1200 / 8
x = 150

Therefore, we can estimate that the turtle population in 2010 was approximately 150.