Factor each polynomial. 18s^2 + 54
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9(2s^2 + 6)
9(2s^2-6)
18(s^2 + 3)
18(s^2 -3)
There are different ways to factor a polynomial, but one common method is to look for common factors among the terms and then use grouping or other techniques. In this case, we can see that both terms have a factor of 18, so we can factor it out first:
18s^2 + 54 = 18(s^2 + 3)
Now we can focus on factoring the expression inside the parentheses. It looks like a simple quadratic expression, which we can factor using the difference of squares pattern:
s^2 + 3 = (s + √3)(s - √3)
Therefore, the fully factored form of the polynomial is:
18s^2 + 54 = 18(s^2 + 3) = 18(s + √3)(s - √3)
To factor the polynomial 18s^2 + 54, we can first factor out the greatest common factor, which is 18:
18s^2 + 54 = 18(s^2 + 3)
Now, we can factor the expression within the parentheses. However, it seems like there might be a mistake in the problem you provided. If we assume that the correct expression is 18s^2 + 54, then we cannot factor it further because s^2 + 3 is not factorable. So the factored form of the polynomial 18s^2 + 54 is:
18s^2 + 54 = 18(s^2 + 3)