The internal energy ∆E of a system is -230 kJ. If the system released 300 kJ, How much work was done in the system? Based on your answer, one of the following answer is correct.
Heat flow is constant
Work is done on the system
The system does work
It is a process were heat flow from the surrounding to the system
The correct answer is: Work is done on the system.
Since the internal energy of the system decreased by -230 kJ, this means that the system lost energy. If the system also released 300 kJ of energy, it means that some of this energy was lost as heat, and some was used to do work. Therefore, work was done on the system to account for the additional energy loss.
To find the work done in the system, we can use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:
ΔE = Q - W
Given that ΔE = -230 kJ and Q = -300 kJ (since the system released heat), we can rearrange the equation to solve for W:
W = Q - ΔE
W = -300 kJ - (-230 kJ)
W = -300 kJ + 230 kJ
W = -70 kJ
Therefore, the work done in the system is -70 kJ.
Based on the result, the correct answer is: The system does work.