The following piece of double stranded DNA encodes a very
short peptide. In the space below, write the sequence of
mRNA that would be synthesized by RNA polymerase from
this piece of DNA if the bottom strand is the template. Then
write the protein sequence in one-letter code that would be
synthesized by the ribosome from that mRNA using the first
reading frame (use Genetic Code Table).
i. 5’-ATGGCTGGGTGCTTTTAA-3’
ii. 3’ –TACCGACCCACGAAAATT-5’
60 RMCM 5
i. 3'-UACCGACCCACGAAAATT-5' (mRNA sequence)
ii. Methionine-Arginine-Cysteine-Methionine (MRCM) (protein sequence)
i. To transcribe the given DNA sequence into mRNA, we need to replace each occurrence of T with its RNA counterpart, which is U.
Template DNA strand: 5’-ATGGCTGGGTGCTTTTAA-3’
mRNA sequence: 3’-UACCGACCCACGAAAATT-5’
ii. To find the protein sequence synthesized by the ribosome from the mRNA sequence, we need to use the Genetic Code Table.
mRNA sequence: 3’-UACCGACCCACGAAAATT-5’
Using the first reading frame, we divide the mRNA sequence into codons, each consisting of three nucleotides. Then we look up each codon in the Genetic Code Table to find the corresponding amino acid.
mRNA codons: UAC-CGA-CCC-ACG-AAA-ATT
Looking up each codon in the Genetic Code Table:
UAC - Tyrosine (Y)
CGA - Arginine (R)
CCC - Proline (P)
ACG - Threonine (T)
AAA - Lysine (K)
ATT - Isoleucine (I)
Protein sequence: YRPTKI