You roll a number cube twice. Find the probability of an even number, and then find the probability of a number that is NOT 2. Write the probability as a fraction in simplest form. plz help
There are six possible outcomes when rolling a number cube: 1, 2, 3, 4, 5, or 6.
The probability of rolling an even number is 50%, since there are three even numbers (2, 4, 6) and three odd numbers (1, 3, 5).
To find the probability of rolling a number that is NOT 2, we need to count the number of possible outcomes that are not 2. There are five possible outcomes: 1, 3, 4, 5, or 6. So the probability of rolling a number that is NOT 2 is 5/6.
Therefore, the probability of rolling an even number AND a number that is NOT 2 is (1/2) x (5/6) = 5/12.
To find the probability of rolling an even number on a number cube, we need to determine the number of favorable outcomes (even numbers) and the total number of possible outcomes (the numbers on the cube).
1. Number of favorable outcomes (even numbers): There are three even numbers on a number cube: 2, 4, and 6.
2. Total number of possible outcomes: A number cube has six sides, so there are six possible numbers that can come up.
Thus, the probability of rolling an even number is given by the fraction:
Number of favorable outcomes / Total number of possible outcomes
= 3/6
Now, to find the probability of rolling a number that is NOT 2:
1. Number of favorable outcomes (not 2): There are five numbers that are not 2 on a number cube: 1, 3, 4, 5, and 6.
2. Total number of possible outcomes: As mentioned before, a number cube has six sides.
Therefore, the probability of rolling a number that is not 2 is given by the fraction:
Number of favorable outcomes / Total number of possible outcomes
= 5/6