In a class of students, the following data table summarizes how many students have a brother or a sister. What is the probability that a student chosen randomly from the class has a brother and a sister?
Has a brother Does not have a brother
Has a sister 2 17
Does not have a sister 4 5
There are a total of 2 + 17 + 4 + 5 = 28 students in the class.
The number of students who have both a brother and a sister is 2.
Therefore, the probability that a student chosen randomly from the class has a brother and a sister is 2/28, which simplifies to 1/14 or approximately 0.0714.
In a class of students, the following data table summarizes the gender of the students and whether they have an A in the class. What is the probability that a student chosen randomly from the class is a female?
Female Male
Has an A 6 15
Does not have an A 2 5
There are a total of 6 + 15 + 2 + 5 = 28 students in the class.
The number of female students in the class is 6 + 2 = 8.
Therefore, the probability that a student chosen randomly from the class is a female is 8/28, which simplifies to 2/7 or approximately 0.286.
In a class of students, the following data table summarizes the gender of the students and whether they have an A in the class. What is the probability that a student chosen randomly from the class is a female?
Female Male
Has an A. 6 15
Does not have an A 2 5
There are a total of 6+15+2+5 = 28 students in the class.
The number of female students in the class is 6+2 = 8.
Therefore, the probability that a student chosen randomly from the class is a female is 8/28, or 2/7, or approximately 0.286.
There is a spinner with 12 equal areas, numbered 1 through 12. If the spinner is spun one time, what is the probability that the result is a multiple of 3 and a multiple of 4?
The multiples of 3 and 4 less than or equal to 12 are 3, 6, 9, and 12. These are the only possible outcomes that satisfy the given condition. So, there are four favorable outcomes out of 12 possible outcomes in total. Therefore, the probability of spinning a multiple of 3 and a multiple of 4 is 4/12, which simplifies to 1/3 or approximately 0.333.
In a certain Algebra 2 class of 26 students, 10 of them play basketball and 5 of them play baseball. There are 3 students who play both sports. What is the probability that a student chosen randomly from the class plays basketball or baseball?
To find the probability that a student chosen randomly from the class plays basketball or baseball, we need to add the number of students who play basketball to the number of students who play baseball, but we need to subtract the number of students who play both sports, since we do not want to count them twice.
Number of students who play basketball or baseball = Number of students who play basketball + Number of students who play baseball - Number of students who play both sports
Number of students who play basketball or baseball = 10 + 5 - 3 = 12
Therefore, out of the 26 students in the class, there are 12 students who play basketball or baseball. So, the probability that a student chosen randomly from the class plays basketball or baseball is 12/26, which simplifies to 6/13 or approximately 0.462.