value Equation in
vertex form 𝒚 = 𝟑𝒙^2 + 4
find Equation of axis
of symmetry
The equation of the axis of symmetry in vertex form is:
𝒙 = –𝒃/2𝒂
In this case, 𝒂 = 3 and 𝒃 = 0. Therefore:
𝒙 = –(0)/2(3)
𝒙 = 0/6
𝒙 = 0
So, the equation of the axis of symmetry is 𝒙 = 0.
To find the equation of the axis of symmetry, we need to determine the x-coordinate of the vertex.
The vertex form equation is y = a(x-h)^2 + k, where the vertex is represented by the coordinates (h, k). In our equation y = 3x^2 + 4, we can see that a = 3, h = 0, and k = 4.
The x-coordinate of the vertex is given by -h, so it would be 0 in this case.
Therefore, the equation of the axis of symmetry is x = 0.