Calculate the force required to stretch an elastic material by 13m. Find the stiffness of the material is 10NM^-1
We can use Hooke's Law to solve this problem:
F = kx
where F is the force required, k is the stiffness of the material, and x is the distance stretched.
Substituting the given values:
F = (10 N/m) * (13 m)
F = 130 N
Therefore, the force required to stretch the elastic material by 13m is 130N.
A force of 0.8N stretches on elastic spring by 20cm. Find the elastic constant of the spring
We can use Hooke's Law to solve this problem:
F = kx
where F is the force applied, k is the stiffness or elastic constant of the spring, and x is the displacement or stretch produced.
In this case, the force applied is 0.8N and the displacement produced is 20cm, or 0.2m. Substituting these values:
0.8N = k * 0.2m
Solving for k:
k = 0.8N / 0.2m
k = 4 N/m
Therefore, the elastic constant of the spring is 4 N/m.
To calculate the force required to stretch an elastic material, we can use Hooke's Law, which states that the force is directly proportional to the extension of the material.
Hooke's Law can be expressed as:
F = k * x,
where F is the force required to stretch the material, k is the stiffness (also known as the spring constant) of the material, and x is the extension.
In this case, we are given that the extension (x) is 13 m and the stiffness (k) is 10 N/m.
Substituting these values into the formula, we get:
F = 10 N/m * 13 m.
Multiplying 10 N/m by 13 m, we find that:
F = 130 N.
Therefore, the force required to stretch the elastic material by 13 m is 130 N.