is C3H8O2+4H2O+3CO2 balanced
Yes, it is balanced.
C3H8O2 + 4H2O + 3CO2 → 3C3H4O3 + 4H2O
is C3H8O2=4H2O+3CO2 balanced
No, this equation is not balanced.
C3H8O2 = 4H2O + 3CO2
To balance it, we need to equalize the number of atoms on both sides of the equation.
C3H8O2 + 5O2 = 4H2O + 3CO2
Now the equation is balanced.
The molar mass of SO2 is 60.09 g/mol. How many molecules of silicon dioxide (SiO2) are there in 45.0 grams of silicon dioxide?
We need to start by calculating the number of moles of SiO2 present in 45.0 grams of SiO2:
Moles of SiO2 = Mass of SiO2 / Molar mass of SiO2
Moles of SiO2 = 45.0 g / 60.08 g/mol = 0.749 moles
Next, we can use Avogadro's number to calculate the number of SiO2 molecules present in 0.749 moles:
Number of SiO2 molecules = Moles of SiO2 x Avogadro's number
Number of SiO2 molecules = 0.749 mol x 6.022 x 10^23 molecules/mol
Number of SiO2 molecules = 4.509 x 10^23 molecules
Therefore, there are approximately 4.509 x 10^23 molecules of SiO2 in 45.0 grams of SiO2.
If 64.0 grams of methane (CH4) react completely with oxygen (O2), how many grams of water will be produced?
The molar mass of methane(CH4) is 16 g/mol. The molar mass of water (H2O) is 18 g/mol.
We can start by writing the balanced chemical equation for the combustion of methane with oxygen:
CH4 + 2O2 → CO2 + 2H2O
This equation tells us that one molecule of methane reacts with two molecules of oxygen to produce one molecule of carbon dioxide and two molecules of water.
Using the molar mass of methane, we can convert 64.0 grams of methane to moles:
Number of moles of CH4 = Mass of CH4 / Molar mass of CH4
Number of moles of CH4 = 64.0 g / 16.0 g/mol = 4.00 mol
From the balanced equation, we can see that two molecules of water are produced for every molecule of methane that reacts. So for 4.00 moles of methane, we can expect to produce:
Number of moles of H2O = 2 x Moles of CH4
Number of moles of H2O = 2 x 4.00 mol = 8.00 mol
Finally, we can convert the number of moles of water to grams using the molar mass of water:
Mass of H2O = Number of moles of H2O x Molar mass of H2O
Mass of H2O = 8.00 mol x 18.0 g/mol = 144 g
Therefore, if 64.0 grams of methane react completely with oxygen, 144 grams of water will be produced.
Which type of decay is a form of nuclear fission?
Nuclear fission is not a form of decay, it is a process that is distinct from radioactivity.
Nuclear fission is the process of splitting an atomic nucleus into two or more smaller nuclei, along with the release of a large amount of energy. This process is usually induced by bombarding a nucleus with neutrons, which causes it to become unstable and break apart.
In contrast, radioactive decay refers to the spontaneous breakdown of an unstable atomic nucleus into smaller nuclei, with the emission of particles (such as alpha or beta particles) or photons (gamma rays).
So, neither alpha decay, beta decay, gamma decay, nor any other type of radioactive decay is a form of nuclear fission.