For each reaction below, write a balanced chemical equation. You must first change the reactants from words to symbols, then predict the products based on your knowledge of the type of reaction indicated. Lastly, balance the equation. (Write your answers on a separate sheet of paper first and then enter it in the answer box to access feedback when you click submit for this assignment).
8.
Propane (C3H8) (combustion reaction).
C3H8 + 5O2 → 3CO2 + 4H2O
Hydrochloric acid and silver nitrate (double displacement).
HCl + AgNO3 → AgCl + HNO3
Copper and silver nitrate (single displacement with copper (II) compound formed).
Cu + 2AgNO3 → Cu(NO3)2 + 2Ag
Answer the following questions and then check your answers. For each of the following problems, write a correctly balanced equation.
17.
Magnesium chloride reacts with ammonium nitrate to form magnesium nitrate and ammonium chloride.
MgCl2 + 2NH4NO3 → Mg(NO3)2 + 2NH4Cl
Ammonia and sulfuric acid react to produce ammonium sulfate.
2NH3 + H2SO4 → (NH4)2SO4
To write a balanced chemical equation for the combustion reaction of propane (C3H8), we first need to understand the reactants and products involved.
The reactant in this case is propane (C3H8), which is a hydrocarbon. During combustion reactions, hydrocarbons react with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).
Let's now write the balanced chemical equation for the combustion of propane:
C3H8 + O2 -> CO2 + H2O
Now, we need to balance the equation.
To balance the equation, we need to ensure that the number of atoms for each element is the same on both sides of the equation.
Let's start with carbon (C):
On the left-hand side, we have 3 carbon atoms (from C3H8). On the right-hand side, we have 1 carbon atom (from CO2). To balance carbon, we need to put a coefficient of 3 in front of CO2:
C3H8 + O2 -> 3CO2 + H2O
Next, let's balance hydrogen (H):
On the left-hand side, we have 8 hydrogen atoms (from C3H8). On the right-hand side, we have 2 hydrogen atoms (from H2O). To balance hydrogen, we need to put a coefficient of 4 in front of H2O:
C3H8 + O2 -> 3CO2 + 4H2O
Finally, let's balance oxygen (O):
On the left-hand side, we have 2 oxygen atoms (from O2). On the right-hand side, we have 10 oxygen atoms (from 3CO2 and 4H2O). To balance oxygen, we need to put a coefficient of 5/2 (which can be written as 2.5) in front of O2:
C3H8 + 2.5O2 -> 3CO2 + 4H2O
However, it's not common to have fractional coefficients in balanced equations, so we can multiply the entire equation by 2 to get rid of the fractional coefficient:
2 C3H8 + 5O2 -> 6CO2 + 8H2O
Now the equation is balanced, with 2 molecules of propane, 5 molecules of oxygen, 6 molecules of carbon dioxide, and 8 molecules of water.
Remember to double-check your balanced equation on your end as well.