A bag contains 4 white, 3 blue, and 5 red marbles.
Find the probability of choosing a red marble, then a white marble if the marbles are replaced.
A. one-twelfth
B. five over thirty-six
C. five-sixths
D. five-twelfths
The probability of choosing a red marble on the first draw is 5/12 since there are 5 red marbles out of 12 total marbles. After replacing the marble, the probability of choosing a white marble on the second draw is 4/12 (or 1/3) since there are 4 white marbles out of 12 total marbles. To find the probability of both events happening together, we multiply the probabilities:
(5/12) * (1/3) = 5/36
So the answer is B. five over thirty-six.
A bag contains 4 white, 3 blue, and 5 red marbles.
Find the probability of choosing 3 blue marbles in a row if the marbles are replaced.
A. two over eleven
B. one over two hundred twenty
C. Fraction 1 over 27 end fraction
D. one over sixty-four
The probability of choosing a blue marble on any given draw is 3/12 (or 1/4) since there are 3 blue marbles out of 12 total marbles. Since we are replacing the marble after each draw, the probability of getting 3 blue marbles in a row is the product of the individual probabilities:
(1/4) * (1/4) * (1/4) = 1/64
So the answer is D. one over sixty-four.
A bag contains 4 white, 3 blue, and 5 red marbles.
Find the probability of choosing a blue marble, then a red marble if the marbles are not replaced.
A. five over forty-four
B. fifteen over thirty-five
C. two-thirds
D. one over fifteen
The probability of choosing a blue marble on the first draw is 3/12 (or 1/4) since there are 3 blue marbles out of 12 total marbles. Since we are not replacing the marble, there are now 11 total marbles left, with 5 of them being red. So the probability of choosing a red marble on the second draw, given that a blue marble was chosen on the first draw, is 5/11. To find the probability of both events happening together, we multiply the probabilities:
(1/4) * (5/11) = 5/44
So the answer is A. five over forty-four.
A bag contains 4 white, 3 blue, and 5 red marbles.
Find the probability of choosing 2 white marbles in a row if the marbles are not replaced.
A. The fraction states 1 over 11.
B. one-ninth
C. two-thirds
D. Start Fraction 1 over 16 End Fraction
The probability of choosing a white marble on the first draw is 4/12 (or 1/3) since there are 4 white marbles out of 12 total marbles. Since we are not replacing the marble, there are now only 11 total marbles left, with 3 of them being white. So the probability of choosing a white marble on the second draw, given that a white marble was chosen on the first draw, is 3/11. To find the probability of both events happening together, we multiply the probabilities:
(1/3) * (3/11) = 1/11
So the answer is A. The fraction states 1 over 11.
One-half of the students at Greendale Middle School take art. Two-thirds of the students take Spanish. Deshawn uses a coin and a standard number cube as a simulation of the students at Greendale Middle School.
Deshawn lets “T” represent a student taking art and “H” represent a student not taking art. He lets the numbers 1, 2, 3, and 4 on the number cube represent a student taking Spanish, and the numbers 5 and 6 represent a student not taking Spanish. The table shows the results of Deshawn’s simulation.
T5
T2
H1
T5
H2
T3
H6
H4
H4
T1
H6
H1
T6
T2
T4
T3
H3
H4
H4
T1
Find the probability that a student at Greendale Middle School takes both art and Spanish.
A. Start Fraction 3 over 20 End Fraction
B. two-fifths
C. start fraction 7 over 20 end fraction
D. one-tenth
To find the probability that a student at Greendale Middle School takes both art and Spanish, we need to look for the outcomes where the student takes both T and 1, 2, 3, or 4 (since those represent taking Spanish). From the table, we can see that there are 3 outcomes like this:
T2
T3
T4
Out of a total of 20 outcomes (from rolling the die and flipping the coin), the probability of getting one of these outcomes is:
3/20
So the answer is A. Start Fraction 3 over 20 End Fraction.
One-half of the students at Greendale Middle School take art. Two-thirds of the students take Spanish. Deshawn uses a coin and a standard number cube as a simulation of the students at Greendale Middle School.
Deshawn lets “T” represent a student taking art and “H” represent a student not taking art. He lets the numbers 1, 2, 3, and 4 on the number cube represent a student taking Spanish, and the numbers 5 and 6 represent a student not taking Spanish. The table shows the results of Deshawn’s simulation.
T5
T2
H1
T5
H2
T3
H6
H4
H4
T1
H6
H1
T6
T2
T4
T3
H3
H4
H4
T1
Find the probability that a student at Greendale Middle School takes neither art nor Spanish.
A. Start Fraction 3 over 20 End Fraction
B. two-fifths
C. start fraction 7 over 20 end fraction
D. one-tenth