What is the probability of selecting a red marble setting it aside and then selecting a Blue Marble if there are four red marbles and seven blue marbles
The probability of selecting a red marble on the first draw is 4/11 because there are four red marbles out of eleven total marbles.
After setting aside the red marble, there are now ten marbles left, of which three are red and seven are blue.
Therefore, the probability of selecting a blue marble on the second draw is 7/10.
To find the probability of both events happening in sequence (selecting a red marble first and then a blue marble), multiply the probability of the first event by the probability of the second event:
4/11 * 7/10 = 28/110 = 14/55
The probability of selecting a red marble and then a blue marble is 14/55 or approximately 0.255.