What is the probability of selecting a red marble replacing it and then selecting a Blue Marble if there are four red and seven blue
The probability of selecting a red marble on the first draw is 4/11. Since the marble is then replaced, the probability of selecting a blue marble on the second draw is still 7/11. Therefore, the probability of selecting a red marble and then a blue marble is:
(4/11) * (7/11) = 28/121
So the probability is approximately 0.231 or 23.1%.