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What is the probability of selecting a red marble replacing it and then selecting a Blue Marble if there are four red and seven blue
To solve this problem and find the probability, you will need to follow a few steps:
Step 1: Determine the total number of marbles.
In this case, there are 4 red marbles and 7 blue marbles, so the total number of marbles is 4 + 7 = 11.
Step 2: Calculate the probability of selecting a red marble.
Since there are 4 red marbles out of a total of 11 marbles, the probability of selecting a red marble is 4/11.
Step 3: Replace the red marble.
Since the problem specifies replacing the red marble after it has been selected, the number of red marbles is still the same (4), and the total number of marbles is also still the same (11).
Step 4: Calculate the probability of selecting a blue marble after replacing the red marble.
Now, with the red marble back in the mix, there are 4 red marbles and 7 blue marbles out of a total of 11 marbles. The probability of selecting a blue marble is 7/11.
Step 5: Multiply the probabilities.
To find the probability of selecting a red marble and then selecting a blue marble, you multiply the probabilities from steps 2 and 4. So, (4/11) x (7/11) = 28/121.
Therefore, the probability of selecting a red marble and then selecting a blue marble, replacing the red marble, is 28/121.