Given that ∠MQL = 180° and ∠XQR = 180°, which equation could be used to solve problems involving the relationships between ∠XQL and ∠MQR?
A. (122 − 1b) − 360 = (146 − 4b)
B. (146 − 4b) + (122 − 1b) = 180
C. (146 − 4b) − (122 − 1b) = 180
D. (146 − 4b) = (122 − 1b)
E. (122 − 1b) − 180 = (146 − 4b)
B. (146 − 4b) + (122 − 1b) = 180
This is because the sum of angles in a straight line is 180°, and both ∠MQL and ∠XQR are straight lines. Using this equation, we can solve for the relationship between ∠XQL and ∠MQR.
The answer was (146 - 4b) = (122 - 1b) You are no help bot.
You are correct. I apologize for the error in my previous response. The correct equation is indeed (146 - 4b) = (122 - 1b). Thank you for bringing this to my attention.
The supplement of an angle X is four times as large as the complement of the angle. Write an equation to find X.
A. 27
B. 30
C. 45
D. 60
E. 36
Which one is it? I need the correct answer. Check before you answer.
Let's use the given information to write an equation to find X.
The supplement of an angle X is 180° - X, and the complement of an angle X is 90° - X.
From the problem, we know that:
180° - X = 4(90° - X)
Simplifying the right side, we get:
180° - X = 360° - 4X
Adding X to both sides, we get:
180° = 360° - 3X
Subtracting 360° from both sides, we get:
-180° = -3X
Dividing both sides by -3, we get:
X = 60°
Therefore, the answer is D. 60.
Find the value of x.
m∠TUV = 172°
m∠TUL = (x + 16)°
m∠LUV = (11x)°
We know that the sum of the angles in a triangle is 180 degrees.
Therefore, we can write the equation:
m∠TUV + m∠TUL + m∠LUV = 180
Substituting the given angle measures, we get:
172 + (x + 16) + 11x = 180
Simplifying the left side, we get:
12x + 188 = 180
Subtracting 188 from both sides, we get:
12x = -8
Dividing both sides by 12, we get:
x = -8/12
Simplifying the fraction, we get:
x = -2/3
Therefore, the value of x is -2/3.