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A radio signal travels at

3.00* 10^8 meters per second. How many seconds will it take for a radio signal to travel from a satellite to the surface of Earth if the satellite is orbiting at a height of
3.54*10^7 meters? Show your work.

Yes, sure. We can use the formula: distance = speed x time, where distance is the total distance travelled by the radio signal, speed is the speed of the signal and time is the time taken for the signal to travel.

Here, the distance travelled by the radio signal is the sum of the radius of the Earth (6.37 x 10^6 meters) and the height of the satellite (3.54 x 10^7 meters).

So, distance = (6.37 x 10^6) + (3.54 x 10^7) = 4.17 x 10^7 meters

We need to find the time taken for the signal to travel this distance.

Using the formula, we have:

distance = speed x time

time = distance / speed

time = (4.17 x 10^7) / (3.00 x 10^8) = 0.139 seconds

Therefore, it will take around 0.139 seconds for the radio signal to travel from the satellite to the surface of the Earth.

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