Each of two urns contains green balls and red balls. Urn I contains 10 green balls and 8 red balls. Urn II contains 3 green balls and 10 red balls. If a ball is drawn from each urn, what is P(red and red)?

Question

Each of two urns contains green balls and red balls. Urn I contains 10 green balls and 8 red balls. Urn II contains 3 green balls and 10 red balls. If a ball is drawn from each urn, what is P(red and red)?

A. The fraction is 23 over 18.
B. start fraction 10 over 27 end fraction
C. start fraction 40 over 117 end fraction
D. start fraction 18 over 31 end fraction

Answer 1

The probability of drawing a red ball from Urn I is 8/18 or 4/9. The probability of drawing a red ball from Urn II is 10/13. To find the probability of both events happening, we multiply the probabilities: (4/9) x (10/13) = (40/117). Therefore, the answer is (C) start fraction 40 over 117 end fraction.