A titration reaction to determine the molarity of an HI solution with known molarity of NaOH was performed. 25.00 mL of 0.125 M NaOH solution was used to titrate a 21.37 mL of HCI to reach the endpoint. What is thelconcentration of the HCI?
The balanced chemical equation for the reaction between NaOH and HCl is:
NaOH + HCl → NaCl + H2O
From the equation, it can be seen that the stoichiometry of the reaction is 1:1. This means that one mole of NaOH reacts with one mole of HCl.
First, let's calculate the number of moles of NaOH used in the titration:
moles of NaOH = molarity x volume (in liters)
moles of NaOH = 0.125 M x 0.025 L
moles of NaOH = 0.003125 mol
Since the stoichiometry of the reaction is 1:1, the number of moles of HCl in the sample is also 0.003125 mol.
Now, let's calculate the concentration of the HCl solution:
molarity of HCl = moles of HCl / volume (in liters)
molarity of HCl = 0.003125 mol / 0.02137 L
molarity of HCl = 0.1460 M
Therefore, the concentration of the HCl solution is 0.1460 M.