Add.
start fraction 5 c over 2 c plus 7 end fraction plus start fraction c minus 28 over 2 c plus 7 end fraction
= (5c/(2c + 7)) + (c - 28)/(2c + 7)
= ((5c + c - 28)/(2c + 7))
= (6c - 28)/(2c + 7)
= 2(3c - 14)/(2c + 7)
Therefore, the simplified expression is 2(3c - 14)/(2c + 7).
Subtract.
start fraction 3 n plus 2 over n plus 4 end fraction minus start fraction n minus 6 over n plus 4 end fraction
A. 2 n plus 8
B. start fraction 2 n minus 4 over n plus 4 end fraction
C. start fraction 2 n minus 8 over n plus 4 end fraction
D. 2
We have:
(3n + 2)/(n + 4) - (n - 6)/(n + 4)
= (3n + 2 - (n - 6))/(n + 4) [finding a common denominator]
= (3n + 2 - n + 6)/(n + 4)
= (2n + 8)/(n + 4)
Therefore, the answer is (A) 2n + 8.
To add the given fractions, we need to find a common denominator. In this case, the denominators are both 2c + 7. To add fractions with the same denominator, we can simply add their numerators.
The numerator of the first fraction is 5c and the numerator of the second fraction is c - 28.
So, the expression can be written as:
(start fraction 5c + c - 28) over (2c + 7).
Next, we combine like terms in the numerator:
5c + c - 28 = 6c - 28.
Therefore, the final sum of the fractions is:
(start fraction 6c - 28) over (2c + 7).