A force of 4n stretches an elastic material by 20mm.what additional force will stretches the material by 3omm?assume that the elastic limit is not exceeded
We can use the concept of Hooke's Law to solve this problem. Hooke's Law states that the force required to extend or compress an elastic material is directly proportional to the extension or compression, as long as the elastic limit is not exceeded. Mathematically, this can be expressed as:
F = kx
where F is the force applied, x is the extension or compression, and k is the spring constant, which is a measure of how stiff the material is. In this problem, we are given that a force of 4N stretches the material by 20mm, so we can use this information to find the value of k:
k = F/x = 4N/20mm = 0.2N/mm
Now we can use this value of k to find the additional force required to stretch the material by 30mm:
F = kx = 0.2N/mm x 30mm = 6N
Therefore, an additional force of 6N is required to stretch the material by 30mm, as long as the elastic limit is not exceeded.