v(r)= k(a-r)r^2 where k is a constant
evaluate v at a.
This is what I got when I solved but it is not correct.
v(a)=k(a-a)a^2
v(a)=ka^2
v(a)=k(a-a)a^2 correct
v(a)=k(0)a^2
v(a)= 0 , zero times anything else is zero
oh i see
To evaluate v(r) at a specific value of r (in this case, at a), you need to substitute the value of r into the equation for v(r) and simplify.
Given the equation: v(r) = k(a - r)r^2
To evaluate v(a), substitute a for r in the equation:
v(a) = k(a - a)a^2
Since (a - a) equals 0, the equation simplifies to:
v(a) = k(0)a^2
Any term multiplied by 0 is zero, so the final result is:
v(a) = 0
So, the correct evaluation of v(a) is zero, not ka^2. It seems there may have been a mistake in your previous calculation.