The table summarizes the results of spinning the spinner shown
Red was spinned 6, blue 5, green 3, and yellow 4
What is th3 theoretical probability of the spinner landing on red
The theoretical probability of the spinner landing on red can be calculated by dividing the number of times red was spun by the total number of spins possible.
Total spins possible = 6 + 5 + 3 + 4 = 18
Probability of spinner landing on red = 6/18 = 1/3
Therefore, the theoretical probability of the spinner landing on red is 1/3 or 0.33.
Two coins were tossed 10 times.
1 hh, 2 tt, 3 ht, 4 th, 5 ht, 6 hh, 7 th, 8 tt, 9 th, 10 ht
What is the experimental probability that at least one of the coins landed on heads? Express th3 probability as a decimal
To find the experimental probability that at least one of the coins landed on heads, we need to count the number of times that at least one head was obtained and divide that by the total number of coin tosses.
Out of the 10 tosses, there were 6 times that at least one head was obtained: 1, 3, 5, 6, 7, and 9.
So the experimental probability is 6/10, which simplifies to 3/5 or 0.6 when expressed as a decimal.
Therefore, the experimental probability that at least one of the coins landed on heads is 0.6.
Two coins were tossed ten times
1hh, 2 tt, 3 ht, 4 th, 5 ht, 6 hh, 7th, 8 tt, 9 th, 10 ht
Make a tree diagram for two coins that are tossed. Find the theoretically probability that at least one coin is heads. Express the probability as a decimal
Here is the tree diagram for the two coins that are tossed:
```
H T
/ \ / \
H T H T
/ \ / \ / \ / \
H T H T H T H T
```
To find the theoretical probability that at least one coin is heads, we need to count the number of outcomes in which at least one coin is heads and divide that by the total number of outcomes.
There are 3 outcomes in which both coins are tails (2, 4, and 8).
Therefore, there are 7 outcomes in which at least one coin is heads.
So the theoretical probability is 7/10, which simplifies to 0.7 when expressed as a decimal.
Therefore, the theoretical probability that at least one coin is heads is 0.7.
A number cube is rolled 100 times
1 22, 2 18, 3 9, 4 11, 5 19, 6 21
Find the experimental probability, and express it as a percent
To find the experimental probability, we count the number of times a particular outcome occurred and divide that by the total number of rolls.
1 was rolled 22 times out of 100 rolls
2 was rolled 18 times out of 100 rolls
3 was rolled 9 times out of 100 rolls
4 was rolled 11 times out of 100 rolls
5 was rolled 19 times out of 100 rolls
6 was rolled 21 times out of 100 rolls
The experimental probability of rolling a 1 is 22/100 = 0.22 or 22% as a percent.
The experimental probability of rolling a 2 is 18/100 = 0.18 or 18% as a percent.
The experimental probability of rolling a 3 is 9/100 = 0.09 or 9% as a percent.
The experimental probability of rolling a 4 is 11/100 = 0.11 or 11% as a percent.
The experimental probability of rolling a 5 is 19/100 = 0.19 or 19% as a percent.
The experimental probability of rolling a 6 is 21/100 = 0.21 or 21% as a percent.
Therefore, the experimental probability as a percent for each outcome is:
1: 22%
2: 18%
3: 9%
4: 11%
5: 19%
6: 21%
A number cube is rolled 100 times
1 22, 2 18, 3 9, 4 11, 5 19, 6 21
Find the experimental probability, and express it as a percent
p(even)=?
To find out the experimental probability of rolling an even number, we need to add up the number of times 2, 4, and 6 were rolled, and then divide the result by the total number of rolls.
2 and 6 were rolled a total of 18 + 21 = 39 times out of 100 rolls
4 was rolled 11 times out of 100 rolls
Total number of rolls = 100
The experimental probability of rolling an even number is (number of times an even number was rolled) / (total number of rolls) = (39 + 11) / 100 = 50 / 100 = 0.5
Therefore, the experimental probability of rolling an even number is 0.5 or 50% as a percent.