mass-mass problem example what masses of CH4 formed when 8.3moles of CO react with H2?
The balanced chemical equation for the reaction between CO and H2 to form CH4 is:
CO + 3H2 -> CH4 + H2O
From this equation, we can see that for every 1 mole of CO that reacts, we need 3 moles of H2. Therefore, if we have 8.3 moles of CO, we will need:
8.3 moles CO x (3 moles H2 / 1 mole CO) = 24.9 moles H2
Now that we have determined the amount of H2 needed, we can use the balanced equation to find the theoretical yield of CH4. For every 1 mole of CH4 produced, we need 1 mole of CO and 3 moles of H2. Therefore, the ratio of moles of CH4 to moles of H2 is 1:3.
So the theoretical yield of CH4 can be calculated as:
24.9 moles H2 x (1 mole CH4 / 3 moles H2) = 8.3 moles CH4
Therefore, if 8.3 moles of CO react with an excess of H2, the theoretical yield of CH4 would be 8.3 moles.