2-bromo-2-methylpropane+NaOCH2CH3+CH3CH2OH

This reaction is a substitution reaction known as an S​N​1 reaction.

First Step:
2-bromo-2-methylpropane undergoes heterolysis in the presence of CH3CH2OH and forms a carbocation and a bromide ion.

(CH3)3CBr + CH3CH2OH → (CH3)3CO​+ + Br​-

Second Step:
Sodium ethoxide (NaOCH2CH3) reacts with the solvent CH3CH2OH to produce sodium ethoxide (NaOCH2CH3) and ethanol.

Na + OCH2CH3− + CH3CH2OH → NaOCH2CH3 + CH3CH2OH

Third Step:
The nucleophile ethoxide ion (OCH2CH3−) attacks the carbocation to form a new compound.

(CH3)3CO​+ + OCH2CH3− → (CH3)3COCH2CH3

The final product is 2-methylpropan-2-ol (Tertiary butyl alcohol).