When throwing an unbiased die, the probability of getting a prime number is
1/2.
This is because there are six possible outcomes when you throw a die (numbers 1 through 6), and exactly three of them are prime numbers (2, 3, and 5). Therefore, the probability of getting a prime number on a single throw is 3 out of 6, or 1/2.
To find the probability of getting a prime number when throwing an unbiased die, we first need to determine the total number of possible outcomes.
When throwing a die, there are 6 possible outcomes, as there are 6 faces on a standard die labeled with the numbers 1 to 6.
Next, we need to determine the number of favorable outcomes, which in this case are the prime numbers that can appear on the die. The prime numbers from 1 to 6 are 2, 3, and 5.
Therefore, the number of favorable outcomes is 3.
To calculate the probability of getting a prime number, we divide the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 3 / 6
Simplifying the fraction, we get:
Probability = 1 / 2
So, the probability of getting a prime number when throwing an unbiased die is 1/2 or 0.5.