Find the number of permutations that can be formed from all the letters of each word: (a) QUEUE; (b) COMMITTEE; (c) PROPOSITION; (d) BASEBALL
(a) QUEUE has 5 letters, but the letter E appears twice. Therefore, the total number of permutations is 5!/2! = 60.
(b) COMMITTEE has 9 letters, but the letters E, T, and M each appear twice. Therefore, the total number of permutations is 9!/2!2!2! = 45,360.
(c) PROPOSITION has 11 letters, but the letters O and P each appear twice. Therefore, the total number of permutations is 11!/2!2! = 3,465,120.
(d) BASEBALL has 8 letters, but the letters A and B each appear twice. Therefore, the total number of permutations is 8!/2!2! = 20,160.