A bag contains 4 yellow marbles and 6 green marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability that the first marble is green and the second one is yellow?
The probability of the first marble being green is 6/10 or 3/5.
After one green marble is removed, there are a total of 9 marbles left, of which 4 are yellow.
Therefore, the probability of the second marble being yellow, given that the first was green and not replaced, is 4/9.
To find the probability of both events happening (first marble green and second marble yellow), we multiply the probabilities:
3/5 * 4/9 = 12/45 or 4/15.
Therefore, the probability that the first marble is green and the second one is yellow is 4/15.