Use the image to answer the question.
An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three horizontal parallelograms joined next to each other. All 4 sides of the middle parallelogram are drawn with dashed lines. The width of the parallelograms is 4 centimeters. The length of the middle parallelogram is 12 centimeters. Two right triangles adjoin the middle parallelogram on the top and bottom 12 centimeter sides, with their hypotenuse sides measuring 15 centimeters and the perpendicular sides measuring 9 centimeters. Right angles are shown at the intersection of the perpendicular sides and the base sides of the triangles.
What is the surface area of the triangular prism whose net is shown?
A:198 cm2
B:252 cm2
C:108 cm2
D:216 cm2
To find the surface area of the triangular prism, we need to find the area of each of the three parallelogram faces and the area of the two triangular faces.
The area of each parallelogram face is base times height, which is 12 cm times 4 cm, giving us 48 cm^2 for each face. Since there are three parallelogram faces, the total area for them is 144 cm^2.
The area of each triangular face is base times height divided by 2, which is (9 cm times 12 cm) divided by 2, giving us 54 cm^2 for each face. Since there are two triangular faces, the total area for them is 108 cm^2.
Adding up the areas of all five faces, we get a total surface area of 144 cm^2 + 108 cm^2, which is equal to 252 cm^2.
Therefore, the answer is B) 252 cm^2.