calculate the energy stored in a spring when it compressed 5 mm by a 60 N force.
The energy stored in a spring is given by the formula:
E = (1/2)kx^2
where E is the energy stored, k is the spring constant, and x is the displacement of the spring from its equilibrium position.
To calculate the spring constant, we can use Hooke's law:
F = kx
where F is the force applied to the spring.
We know that the spring is compressed by 5 mm (or 0.005 m) by a force of 60 N, so:
k = F/x = 60/0.005 = 12000 N/m
Now we can calculate the energy stored in the spring:
E = (1/2)kx^2 = (1/2)(12000)(0.005^2) = 0.15 J
Therefore, the energy stored in the spring when it is compressed 5 mm by a 60 N force is 0.15 J.