A bag contains tiles with the letters P-R-O-B-A-B-I-L-I-T-Y. Tyler chooses a tile without looking and doesn't replace it. He chooses a second tile without looking. What is the probability that he will choose the letter I both times?
1/55
2/55
2/121
3/121
The probability of choosing the letter I on the first draw is 2/12 (since there are two I's out of a total of 12 letters). Since Tyler does not replace the first tile, there is now one less tile in the bag and one less I, so the probability of choosing another I on the second draw is now 1/11. Therefore, the probability of choosing I twice in a row is:
(2/12) x (1/11) = 2/132
Simplifying, we get:
2/132 = 1/66
Therefore, the answer is not given in the options.
A sandwich shop offers the following toppings. How many two-topping sandwiches can you make?
- lettuce
- tomato
- Bacon
- Cheese
- Mustard
(1 point)
8
10
12
20
To find the number of two-topping sandwiches that can be made, we need to use the combination formula:
nCx = n! / (x! * (n-x)!)
where n is the total number of toppings and x is the number of toppings we want to choose (in this case, 2).
Plugging in the numbers, we get:
5C2 = 5! / (2! * (5-2)!)
= 5! / (2! * 3!)
= (5 * 4 * 3 * 2 * 1) / [(2 * 1) * (3 * 2 * 1)]
= 10
Therefore, there are 10 two-topping sandwiches that can be made.
Answer: 10.
To find the probability of Tyler choosing the letter "I" both times, we need to determine the number of ways he can choose the letter "I" on the first and second draw, divided by the total number of possible outcomes.
First, let's find the number of ways Tyler can choose the letter "I" on the first draw. There are 11 tiles in total, and one of them is the letter "I". So the probability of drawing the letter "I" on the first draw is 1/11.
After the first draw, Tyler does not replace the tile he selected. So, for the second draw, there will only be 10 tiles left in the bag, with one of them being the letter "I". Thus, the probability of drawing the letter "I" on the second draw, given that he already drew it on the first draw, is 1/10.
To find the probability of both events happening, we multiply the probabilities of the individual events together. So, the probability of Tyler choosing the letter "I" on both the first and second draw is (1/11) * (1/10) = 1/110.
Therefore, the correct answer is 1/110, not any of the options given.