A spring of force constant dealing of 300NM^-1 is compressed such as it's length shorting by 3cm calculate the energy stored in the spring.
We can use the formula for the potential energy stored in a spring:
U = (1/2)kx^2
where U is the energy stored, k is the force constant, and x is the displacement from the equilibrium position.
In this case, k = 300 N/m and x = 0.03 m. Plugging these values into the formula, we get:
U = (1/2)(300 N/m)(0.03 m)^2
U = 0.135 J
Therefore, the energy stored in the spring is 0.135 joules.