There are two complementary angles, ∠5 and ∠6. If ∠5=39°, what equation can you write to solve for ∠6?
The sum of complementary angles is 90°. Therefore, we can write the equation:
∠5 + ∠6 = 90°
Substituting ∠5 = 39°, we get:
39° + ∠6 = 90°
Solving for ∠6, we subtract 39° from both sides:
∠6 = 90° - 39°
∠6 = 51°
Therefore, the measure of ∠6 is 51°.
There are two complementary angles, ∠5 and ∠6. If ∠5=39°, what equation can you write to solve for ∠6?
x = 39
x+39°=90°
x+39°=180°
x = 180°−39°
I'm sorry, but your equations are incorrect. The correct equation to solve for ∠6 is:
∠5 + ∠6 = 90°
Since we are given that ∠5 = 39°, we can substitute this value in the equation:
39° + ∠6 = 90°
To solve for ∠6, we subtract 39° from both sides:
∠6 = 90° - 39°
∠6 = 51°
Therefore, the measure of ∠6 is 51°.
Two angles in a diagram are supplementary. If ∠1=77°, what equation can you write to solve for ∠2?
x+77°=180°
x=77°
x+77°=90°
x=90°−77°
I'm sorry, but your equations are incorrect. The correct equation to solve for ∠2 is:
∠1 + ∠2 = 180°
Since we are given that ∠1 = 77°, we can substitute this value in the equation:
77° + ∠2 = 180°
To solve for ∠2, we subtract 77° from both sides:
∠2 = 180° - 77°
∠2 = 103°
Therefore, the measure of ∠2 is 103°.
There are two complementary angles, ∠5 and ∠6. If ∠5=39°, what equation can you write to solve for ∠6?
A. x = 39
B. x+39°=90°
C. x+39°=180°
D. x = 180°−39°
The correct equation to solve for ∠6 is:
B. x+39°=90°
Since the sum of complementary angles is 90°, we can write the equation ∠5 + ∠6 = 90°. Substituting ∠5 = 39°, we get 39° + ∠6 = 90°.
We can then simplify the equation to x + 39° = 90° by replacing ∠6 with x. Therefore, the correct answer is option B.