what is the solubility of calcium sulphate in M, g/L, and g/100 mL?
Write out conversion steps.
The solubility of calcium sulphate varies depending on temperature and pressure. At room temperature, the solubility of calcium sulphate is approximately 0.21 grams per 100 milliliters of water.
To convert this to Molarity:
1. Calculate the molar mass of calcium sulphate (CaSO4) = 136.14 g/mol
2. Divide grams per 100 mL by molar mass to get moles per 100 mL:
0.21 g/100 mL ÷ 136.14 g/mol = 1.54 x 10^-3 mol/100 mL
3. Convert moles per 100 mL to moles per liter by multiplying by 10:
1.54 x 10^-3 mol/100 mL x 10 = 1.54 x 10^-2 mol/L
4. The solubility of calcium sulphate in M is therefore 1.54 x 10^-2 M.
To convert this to g/L:
1. Multiply the molarity by the molar mass:
1.54 x 10^-2 mol/L x 136.14 g/mol = 2.09 g/L
2. The solubility of calcium sulphate in g/L is therefore 2.09 g/L.
To convert this to g/100 mL:
1. Divide the solubility in g/L by 10 to get g per 100 mL:
2.09 g/L ÷ 10 = 0.209 g/100 mL
2. The solubility of calcium sulphate in g/100 mL is therefore 0.209 g/100 mL.