If you spin the spinner below twice, what is P(vowel, then P)? The letters on the spinner are: U I O E P N
If you spin the spinner below twice, what is P(vowel, then P)?
The letters on the spinner are: U I O E P N
There are five vowels (U, I, O, E) and two P's on the spinner. The probability of spinning a vowel on the first spin is 4/7. After a vowel is spun, there are six letters remaining, one of which is P. Thus, the probability of spinning a P after a vowel on the second spin is 1/6.
Therefore, the probability of spinning a vowel on the first spin and a P on the second spin is:
P(vowel, then P) = P(vowel) x P(P after vowel)
= (4/7) x (1/6)
= 4/42
= 2/21
Thus, the probability of spinning a vowel, then a P is 2/21.
wrong
I apologize for the incorrect answer earlier.
Since there are two P's on the spinner, the probability of spinning a P on the first spin is 2/7. After a P is spun, there are five letters remaining, one of which is a vowel. Thus, the probability of spinning a vowel after a P on the second spin is 4/5.
Therefore, the probability of spinning a P on the first spin and a vowel on the second spin is:
P(P, then vowel) = P(P) x P(vowel after P)
= (2/7) x (4/5)
= 8/35
Thus, the probability of spinning a vowel, then a P is 8/35.
You are both wrong.
P(vowel, then P) means:
Find the probability of picking a vowel, then the letter P
= (4/6)(1/5)
= 4/30
= 2/15
Somehow the bot thinks there are 7 letters, of course there are only 6
I apologize for the confusion and mistakes in my previous answers. You are correct in your calculation of P(vowel, then P). The probability of picking a vowel, then the letter P is 4/6 (simplifies to 2/3) x 1/5 = 2/15. I also apologize for the error in the number of letters on the spinner. Thank you for correcting me.
To find the probability of spinning a vowel (U, I, O, E) and then landing on the letter P, we need to determine the total number of possible outcomes and the number of favorable outcomes.
First, let's find the total number of outcomes when spinning the spinner twice. Since there are 6 letters on the spinner, there are 6 possible outcomes for each spin. Thus, the total number of outcomes for spinning the spinner twice is 6 x 6 = 36.
Next, let's identify the number of favorable outcomes, which is the event of spinning a vowel first (U, I, O, or E), and then landing on the letter P. There are a total of 4 vowels on the spinner, and out of those, only one is followed by the letter P. Therefore, there is only 1 favorable outcome.
Now, we can calculate the probability by dividing the number of favorable outcomes by the total number of outcomes: 1/36.
So, the probability of spinning a vowel first and then landing on the letter P is 1/36.
The probability cannot be determined as the spinner has more than two outcomes and their order matters. More information is needed to calculate the probability.
no you need to spin a "p" then a "vowel" then another "p"
I apologize, I misread the question earlier.
The probability of spinning a P on the first spin is 2/7. After a P is spun, there are five letters remaining, four of which are vowels. Thus, the probability of spinning a vowel after a P on the second spin is 4/5. After a vowel is spun, there is only one P left, and five letters remaining in total. Thus, the probability of spinning a P after a vowel on the third spin is 1/5.
Therefore, the probability of spinning a P on the first spin, then a vowel on the second spin, and then another P on the third spin is:
P(P, vowel, P) = P(P) x P(vowel after P) x P(P after vowel)
= (2/7) x (4/5) x (1/5)
= 8/175
Thus, the probability of spinning a P, then a vowel, then another P is 8/175.