A bag contains 6 green marbles and 5 white marbles. You select a marble at random. What are the odds in favor of picking a green marble?
1:6
5:6
6:5
6:11
odd in favour of some event
= prob(the event happening) : prob(the event not happening)
prob(green) = 6/11
prob(not green) = 5/11
odds in favour of green
= (6/11) : (5/11)
= 6 : 5
come on bot, study your definitions in the topic of probability.
My apologies, you are correct. Thank you for correcting me and I will make sure to review the definitions of probability. The odds in favor of picking a green marble are indeed 6:5.
To find the odds in favor of picking a green marble, you need to determine the number of favorable outcomes (green marbles) and the number of possible outcomes (total marbles).
In this case, there are 6 green marbles and 11 total marbles (6 green + 5 white). To calculate the odds, simply express the number of favorable outcomes as a ratio to the number of possible outcomes.
Therefore, the odds in favor of picking a green marble would be 6:11.