Evaluate exactly, using the Fundamental Theorem of Calculus:
∫^s_06e^xdx=
By the Fundamental Theorem of Calculus, we have:
∫^s_06e^xdx = [e^x]6^s
To evaluate this, we substitute s and 6 into the expression and subtract:
[e^s] - [e^6]
Therefore, the exact value of the integral is:
e^s - e^6