9. Start Fraction 100 superscript 12 baseline over 100 superscript 8 baseline End Fraction (1 point)
100 superscript Start Fraction 12 over 8 End Fraction baseline
10096
1004
10020
10. Start Fraction x superscript 16 baseline over x superscript 3 baseline End Fraction (1 point)
Lower x superscript Start Fraction 16 over 3 End Fraction baseline
x48
x19
x13
11. 43 ∙ 412 (1 point)
436
415
412
49
12. 44 ∙ 444 (1 point)
4176
448
440
428
Write the value of the expression.
13. Start Fraction 2 cubed over 2 cubed End Fraction (1 point)
0
1
2
3
14. Start Fraction 3 cubed over 3 superscript 6 baseline End Fraction (1 point)
start fraction 1 over 27 end fraction
start fraction 1 over 9 end fraction
9
–27
Multiply. Write the result in scientific notation.
15. (8 ∙ 103)(7 ∙ 105) (1 point)
5.6 ∙ 1016
5.6 ∙ 109
1.5 ∙ 1016
1.5 ∙ 109
16. (1.7 ∙ 10–4)(5 ∙ 10–5) (1 point)
8.5 ∙ 10–9
8.5 ∙ 1020
6.7 ∙ 10–9
6.7 ∙ 1020
Simplify the expression.
17. 8t5 ∙ 8t5 (1 point)
64t25
64t10
16t10
16t5
18. –6(4x + 9) (1 point)
10x – 54
10x + 54
–24x + 54
–24x – 54
Simplify the expression.
19. 4k2(–3k2 – 4k + 5) (1 point)
–12k4 – 16k3 + 20k2
12k4 – 16k3 + 9k2
–12k3 + 20k
k4 + 9k2
20. (–4x) ∙ 9x2 (1 point)
–36x3
–36x2
5x3
5x2
21. (7y2 – 3y) + (8y2 – 8y) (1 point)
56y2 – 24y
15y2 – 11y
–y2 + 5y
y2 – 5y
Short Answer
Note: For questions 22–23, your teacher will grade your response to ensure you receive proper credit for your answer.
22. Look at the given triangles.
Two triangles are shown
The blue triangle is a right triangle. The vertical leg is labeled with the expression 4 x plus 2. The horizontal leg is labeled with the expression 5 x minus 4. The hypotenuse is labeled with the expression 7 x plus 7.
The red triangle is a right triangle. The vertical leg is labeled with the expression x plus 3. The horizontal leg is labeled with the expression x plus 7. The hypotenuse is labeled with the expression 2 x minus 5.
a. Write an expression in simplest form for the perimeter of each triangle.
b. Write another expression in simplest form that shows the difference between the perimeter of the larger triangle and the perimeter of the smaller triangle.
a. Perimeter of blue triangle = 4x + 2 + 5x - 4 + 7x + 7 = 16x + 5
Perimeter of red triangle = x + 3 + x + 7 + 2x - 5 = 4x + 5
b. Perimeter difference = (16x + 5) - (4x + 5) = 12x