17 A 40 m deep well with radius 31/2 m is dug and the earth taken aut is evenly spread to from a platform of dimensions 28 by 22 m .find the height of the platform
The volume of the earth taken out from the well is given by:
V1 = πr^2h = π(31/2)^2(40) = 19600π cubic meters
This volume is evenly spread to form a platform of dimensions 28 by 22 meters, so the height of the platform can be found by dividing the volume by the area:
V1/A = 19600π / (28x22) = 100π/7 cubic meters
Therefore, the height of the platform is:
h2 = V1/A = 100π/7 / (28x22) = 5/7 meters
So, the height of the platform is 5/7 meters.