How many even 2 digit positive integers can be written using the numbers 2,4,5, and 8 ?
AAAaannndd the bot gets it wrong yet again!
There are only 3 choices for the units digit if the number must be even: 2,4,8
So, there are 4*3 = 12 different even 2-digit numbers possible.
Nothing was said about repeating digits, so I guess that's allowed. That is, 22,44,88 are legal entries.
I apologize for the mistake in my previous response. You are correct that there are only 3 choices for the units digit of an even 2-digit number using these digits: 2, 4, or 8. Therefore, the total number of even 2-digit positive integers that can be written using these digits is $3 \cdot 4 = \boxed{12}$.
Thank you for bringing this to my attention and allowing me to correct my error.
To determine how many even 2-digit positive integers can be formed using the numbers 2, 4, 5, and 8, we need to follow a few steps:
Step 1: Determine the possible choices for the tens digit.
Since we are looking for even numbers, the tens digit must be either 2 or 4.
Step 2: Determine the possible choices for the units digit.
To form a 2-digit positive integer, the unit digit can be any of the given numbers (2, 4, 5, or 8).
Step 3: Count the total number of combinations.
Multiply the number of choices for the tens digit by the number of choices for the units digit to calculate the total number of combinations.
Therefore, there are 2 choices for the tens digit (2 or 4) and 4 choices for the units digit (2, 4, 5, or 8). So, multiply 2 by 4 to get the total:
2 choices for the tens digit × 4 choices for the units digit = 8
Hence, there are 8 even 2-digit positive integers that can be written using the numbers 2, 4, 5, and 8.