Evaluate. Write your answer in simplified, rationalized form. Do not round.

csc 60°

Recall that $\csc \theta = \frac{1}{\sin \theta}$. Therefore, $\csc 60^\circ = \frac{1}{\sin 60^\circ}$. We recognize that $\sin 60^\circ = \frac{\sqrt{3}}{2}$, so $\csc 60^\circ = \frac{1}{\frac{\sqrt{3}}{2}} = \frac{2}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}} = \boxed{\frac{2\sqrt{3}}{3}}$.