A basket contains the following pieces of fruit: 3 apples, 2 oranges, 2 bananas, 2 pears, and 5 peaches. Jameson picks a fruit at random and does not replace it. Then Brittany picks a fruit at random. What is the probability that Jameson gets a banana and Brittany gets a pear?
4/27
1/49
2/91
27/91
The probability of Jameson picking a banana is 2/14, or 1/7. After Jameson picks a fruit, there are 9 fruits remaining, including one pear. So the probability of Brittany picking a pear after Jameson has picked a banana is 1/9.
The probability of these two events happening together (Jameson picking a banana and Brittany picking a pear) is the product of their individual probabilities:
(1/7) x (1/9) = 1/63
Therefore, the correct answer is:
2/91