3.22g of hydrated sodium sulphate na2so4xh2o were heated to a constant mass of 1.42g determine the value of x in the formula(Na=23.0,s=32.0,0=16,h=1)

First, we need to find the mass of anhydrous sodium sulfate (Na2SO4):

3.22g - 1.42g = 1.80g

Next, we need to calculate the moles of anhydrous Na2SO4:

1.80g / 142g/mol = 0.0127 mol

Since Na2SO4 reacts in a 1:1 ratio with water, the number of moles of water in the original hydrated compound is also 0.0127 mol.

Now, we can use the molar mass of the hydrated compound (142g/mol) to calculate the mass of water:

142g/mol - 112g/mol = 30g/mol

30g/mol x 0.0127 mol = 0.381g

Finally, we can use the mass of water and the mass of the hydrated compound to determine the value of x:

xH2O = (mass of water / mass of hydrated compound) x formula weight of water

xH2O = (0.381g / 3.22g) x 18g/mol

xH2O = 0.134

Therefore, the value of x in the formula Na2SO4·xH2O is approximately 0.134.

To determine the value of x in the formula (Na2SO4·xH2O), we need to calculate the molar mass of the hydrated sodium sulphate (Na2SO4·xH2O).

Let's break down the molar mass calculation step-by-step:

1. Sodium (Na) has a molar mass of 23.0 g/mol.
2. Sulfur (S) has a molar mass of 32.0 g/mol.
3. Oxygen (O) has a molar mass of 16.0 g/mol.
4. Hydrogen (H) has a molar mass of 1.0 g/mol.

The molar mass of sodium sulphate (Na2SO4) is calculated as follows:
(2 × Na) + S + (4 × O)
(2 × 23.0) + 32.0 + (4 × 16.0)
46.0 + 32.0 + 64.0
142.0 g/mol

Now, let's find the molar mass of water (H2O):
2 × H + O
(2 × 1.0) + 16.0
2.0 + 16.0
18.0 g/mol

Considering the hydrated formula of sodium sulphate (Na2SO4·xH2O), the total molar mass is:
142.0 + (x × 18.0) g/mol

Next, we have to find the moles of hydrated sodium sulphate used by using the given mass of 3.22g:
Moles = Mass / Molar mass
Moles = 3.22g / (142.0 + (x × 18.0)) g/mol

The mass of the anhydrous sodium sulphate (Na2SO4) is given as 1.42g. The molar mass of anhydrous sodium sulphate is 142.0 g/mol.

Now, we can set up an equation based on the conservation of mass:
Moles of hydrated sodium sulphate = Moles of anhydrous sodium sulphate

Therefore, we can write the equation as follows:
3.22g / (142.0 + (x × 18.0)) g/mol = 1.42g / 142.0 g/mol

Cross-multiplying the equation, we get:
(3.22g)(142.0 g/mol) = (1.42g)(142.0 + (x × 18.0)) g/mol

Simplifying, we have:
457.24 = 201.24 + (x × 25.56)

Rearranging the equation, we get:
(x × 25.56) = 457.24 - 201.24
(x × 25.56) = 256.0

Finally, divide both sides of the equation by 25.56 to solve for x:
x = 256.0 / 25.56

Calculating, we find:
x = 10

Therefore, the value of x in the formula Na2SO4·xH2O is 10.

To determine the value of x in the formula Na2SO4·xH2O, we need to use the information given about the mass of the hydrated sodium sulphate before and after heating.

1. Calculate the molar mass of the hydrated sodium sulphate:
- Molar mass of Na = 23.0 g/mol
- Molar mass of S = 32.0 g/mol
- Molar mass of O = 16.0 g/mol
- Molar mass of H = 1.0 g/mol
- Molar mass of H2O = (2 * H) + O = (2 * 1.0) + 16.0 = 18.0 g/mol
- Molar mass of Na2SO4 x H2O = (2 * Na) + S + (4 * O) + (x * 18.0)

2. Calculate the moles of hydrated sodium sulphate:
- Moles = Mass / Molar mass
- Moles of hydrated sodium sulphate = 3.22 g / (2 * Na + S + 4 * O + x * 18.0)

3. Calculate the moles of anhydrous sodium sulphate after heating:
- Moles = Mass / Molar mass
- Moles of anhydrous sodium sulphate = 1.42 g / (2 * Na + S + 4 * O)

4. Since the reaction results in a constant mass after heating, the moles of anhydrous sodium sulphate after heating should be equal to the moles of hydrated sodium sulphate before heating:
- Moles of anhydrous sodium sulphate = Moles of hydrated sodium sulphate
- 1.42 g / (2 * Na + S + 4 * O) = 3.22 g / (2 * Na + S + 4 * O + x * 18.0)

5. Rearrange the equation to solve for x:
- Cross multiply the equation and solve for x:
- (1.42 g * (2 * Na + S + 4 * O + x * 18.0)) = (3.22 g * (2 * Na + S + 4 * O))
- Simplify the equation by substituting the atomic masses of the elements:
- (1.42 g * (2 * 23.0 + 32.0 + 4 * 16.0 + x * 18.0)) = (3.22 g * (2 * 23.0 + 32.0 + 4 * 16.0))
- Solve the equation for x.

By following these calculation steps, you should be able to determine the value of x in the formula Na2SO4·xH2O.