The figure below shows two half-circles at the ends of a rectangle with the dimensions shown.

Question

The figure below shows two half-circles at the ends of a rectangle with the dimensions shown.

A figure is shown with two half-circles at the ends of a rectangle. The rectangle at the center has a width of 20 inches and a height of 4 inches. The 4 inch ends of the rectangle are diameters of the two half-circles.
Which is closest to the area of the figure in square inches?
A. 93
B. 130
C. 86
D. 105

Answer 1

The area of the rectangle is $20\cdot 4=80$. The area of both half circles is $\frac{1}{2}\cdot\left(\frac{4}{2}\right)^2\pi=2\pi$, so the total area of both half circles is $4\pi$. Therefore, the total area of the figure is $80+4\pi\approx \boxed{\textbf{(A)}\ 93}$.